POJ-2141-Message Decowding-解题报告

注意运用getline函数来获得一行字符串。

#include <iostream>
#include <string>
#include <ctype.h>
using namespace std;
int main()
{
    string keyStr, msgDecStr, aLine;
    getline(cin, aLine);
    keyStr = aLine;
    const char *key = keyStr.c_str();
    getline(cin, aLine);
    msgDecStr = aLine;
    const char *msgDec = msgDecStr.c_str();
    char msg[100];
    char c, c2, c3;
    unsigned int i;
    for(i = 0; i < msgDecStr.length(); ++i) {
        c = msgDec[i];
        if(isupper(c)) {
            c2 = key[c - 'A'];
            c3 = toupper(c2);
            msg[i] = c3;
        } else if(c == ' ') {
            msg[i] = c;
        } else {
            c2 = key[c - 'a'];
            msg[i] = c2;
        }
    }
    msg[i] = '/0';
    cout << msg << endl;
    return 0;
}